You are given an integer array nums
and two integers l
and r
. Your task is to find the minimum sum of a subarray whose size is between l
and r
(inclusive) and whose sum is greater than 0.
Return the minimum sum of such a subarray. If no such subarray exists, return -1.
A subarray is a contiguous non-empty sequence of elements within an array.
Example 1:
Input: nums = [3, -2, 1, 4], l = 2, r = 3
Output: 1
Explanation:
The subarrays of length between l = 2
and r = 3
where the sum is greater than 0 are:
[3, -2]
with a sum of 1[1, 4]
with a sum of 5[3, -2, 1]
with a sum of 2[-2, 1, 4]
with a sum of 3Out of these, the subarray [3, -2]
has a sum of 1, which is the smallest positive sum. Hence, the answer is 1.
Example 2:
Input: nums = [-2, 2, -3, 1], l = 2, r = 3
Output: -1
Explanation:
There is no subarray of length between l
and r
that has a sum greater than 0. So, the answer is -1.
Example 3:
Input: nums = [1, 2, 3, 4], l = 2, r = 4
Output: 3
Explanation:
The subarray [1, 2]
has a length of 2 and the minimum sum greater than 0. So, the answer is 3.
Constraints:
1 <= nums.length <= 100
1 <= l <= r <= nums.length
-1000 <= nums[i] <= 1000
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